(x^1/3-2y^2/3)^2

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Solution for (x^1/3-2y^2/3)^2 equation: 


x in (-oo:+oo)

((x^1)/3-((2*y^2)/3))^2 = 0

(x/3+(-2/3)*y^2)^2 = 0

(1/3*x-2/3*y^2)^2 = 0

1/3*x-2/3*y^2 = 0 // + -2/3*y^2

1/3*x = -(-2/3*y^2) // : 1/3

x = (-(-2/3*y^2))/1/3

x = 2*y^2

x in { 2*y^2, 2*y^2 }

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